calling high iq'es

[Potter]

So if you went out on a boat with a bunch of big, light, hollow peices of plastic, that have no air inside them so they will sink, if you throw them out that the amount ogf water thre y displaced is eiqual to there tiny effect of displacement while on the boat?

[sam]

yes, because the mass doesn't change

[Gumby]

No one has gotten it correctly yet. The level of the water will drop.

The weight of the boat doesn't matter. It is constant throughout the problem: always floating.

the level of the water is dependent on the amount of water displaced. (like if you sit in a bath tub, the water will rise at the edge of the tub)

A floating object displaces an amount of water equal to its WEIGHT. A sunken object displaces an amount of water equal to its VOLUME.

When the rocks are in the boat, the volume of water that is displaced must have mass equal to the total mass of the boat and rocks.

When the rocks are at the bottom, they are displacing a volume of water equal to their total volume. Since the rocks sink, they are more dense than water. Thus when floating in the boat, a larger volume of water is displaced than when when they are sunk.

Here's how you can look at it mathematically if you are an algebra buff...

B= mass of boat
R= mass of rocks
V= volume of water displaced (the key factor here)
Dr= Density of rocks (density equals mass divided by volume)
Dw= Density of water
Given that DR>DW...

initial conditions: rocks are in boat and it all floats. The mass of displaced water must equal the mass of the floating system.

V1*DW=B+R
V1=(B+R)/Dw=B/Dw + R/Dw

ending conditions, boat is floating and rocks are sunk. The total water displaced results from the mass of the boat and the volume of the rocks

V2=B/Dw + R/Dr

Now compare the result from the initial condition to the result form the ending condition

V1=B/Dw + R/Dw
V2=B/Dw + R/Dr

The B/Dw appears in both equations so it can just be ignored (this is why the mass of the boat really doesn't matter) and you are left comparing R/Dw to R/Dr and since we said that Dr>Dw, then R/Dw>R/Dr, therefore V1>V2 meaning more water is displaced in the initial conditions than the ending conditions which means the water level dropped.

[Riot]

3. Riot is present.

The third is optional, but recommended. If Riot is not there, then he might be angered and destroy it.

You're the only one who knows what they're talking about.

[SoDeepPolaris]

3. Riot is present.

The third is optional, but recommended. If Riot is not there, then he might be angered and destroy it.

You're the only one who knows what they're talking about.

Chuck Norris is the diet-Coke of Riot's, just one calorie, not even enough.

But I again, back on topic, agree with Gumby.

[Potter]

I seriosly doubt anyone will get this, but try without going to google.



A bear walks south for one kilometer, then it walks west for one kilometer, then it walks north for one kilometer and ends up at the same point from which it started. What color was the bear?

[Green Tea]

I seriosly doubt anyone will get this, but try without going to google.



A bear walks south for one kilometer, then it walks west for one kilometer, then it walks north for one kilometer and ends up at the same point from which it started. What color was the bear?

White, because it's a polar bear. assuming that the pole is directly magnetic north (which it is not)


Here's one:

Some call me man, but I am never wed. A body I was given, but I will never live. A mouth I was given but I will never breathe. Water makes me live and the sun slowly kills me. What am I?

[Fagulous]

I seriosly doubt anyone will get this, but try without going to google.



A bear walks south for one kilometer, then it walks west for one kilometer, then it walks north for one kilometer and ends up at the same point from which it started. What color was the bear?

Potter you're not that fucking smart, and give us all a little credit you fucking faggot.

I figured that out in 3rd grade, I'm sure a lot of other people here did too.

[sam]

Here's one:

Some call me man, but I am never wed. A body I was given, but I will never live. A mouth I was given but I will never breathe. Water makes me live and the sun slowly kills me. What am I?

venus flytrap?

but seriously, jesus.

also if i remember math correctly, mass and voulme are related and interchangeable. Hence why the water displacement doesn't change. You can go from volume to mass assuming density is 1 and since we're on a boat, we can always assume that it will be 1 since water has a density of 1.

but i may also not remember math so yeah.

I was right! M=DV for water displacement. Thinking further the only reason I can see as it going up more after throwing the rock in is because the mass of the rock is on the boat, which is less dense then water but we assume that the boat is in a tank where it is free floating and not "cramped" so it shouldn't matter?

So for math because I'm bored:

Water displacement with rock on boat:

M=DV

V=Water displaced
D=Water density (since we are measuring water displaced we use the density of the water not the rock)
r=Mass of Rock
b=Mass of Boat

V=(r+b)/D
V=(r+b)/1
V=r+b

Water displacement with rock off boat:

M=DV

V=Water displaced
D=Water density (since we are measuring water displaced we use the density of the water not the rock)
r=Mass of Rock
b=Mass of Boat

V=r/D+b/D
V=r/1+b/1
V=r+b

right?

[sam]

an experiment! and everyone can do it!

What you need:

a large bowl
a cup or waterproof box
water
gravel

take the large bowl and fill it to the absolute rim with water. you must make a miniscus. Water has surface tension and can actually bubble out over the rim but not spill. You want this. It's not as important right now, unless you want numbers.

Put the gravel in the boat and slowly and gently put the boat on the water...weeee water goes everywhere!!! (have a towel!)

now pour more water in while the boat is on the water to recreate the miniscus. This is the boat with a rock in it, any more mass would cause water to overflow.

GENTLY pull the boat up some to reduce the water level and remove the rock.
GENTLY place the rock in the bowl...I find running it along the wall the easiest.

What happens? No water comes out!!!

[Green Tea]

Here's one:

Some call me man, but I am never wed. A body I was given, but I will never live. A mouth I was given but I will never breathe. Water makes me live and the sun slowly kills me. What am I?

venus flytrap?

but seriously, jesus.
right?

Not venus flytrap or jesus. it's a snowman

[Potter]

I seriosly doubt anyone will get this, but try without going to google.



A bear walks south for one kilometer, then it walks west for one kilometer, then it walks north for one kilometer and ends up at the same point from which it started. What color was the bear?

Potter you're not that fucking smart, and give us all a little credit you fucking faggot.

I figured that out in 3rd grade, I'm sure a lot of other people here did too.

wtf? did ieevr say i was remotely smart? not at all. And i found that question on google, never heard of it before, and it sounded extremely hard to me. SORRYRYSYDHHJK

[Gumby]

Here's one:

Some call me man, but I am never wed. A body I was given, but I will never live. A mouth I was given but I will never breathe. Water makes me live and the sun slowly kills me. What am I?

venus flytrap?

but seriously, jesus.

also if i remember math correctly, mass and voulme are related and interchangeable. Hence why the water displacement doesn't change. You can go from volume to mass assuming density is 1 and since we're on a boat, we can always assume that it will be 1 since water has a density of 1.

but i may also not remember math so yeah.

I was right! M=DV for water displacement. Thinking further the only reason I can see as it going up more after throwing the rock in is because the mass of the rock is on the boat, which is less dense then water but we assume that the boat is in a tank where it is free floating and not "cramped" so it shouldn't matter?

So for math because I'm bored:

Water displacement with rock on boat:

M=DV

V=Water displaced
D=Water density (since we are measuring water displaced we use the density of the water not the rock)
r=Mass of Rock
b=Mass of Boat

V=(r+b)/D
V=(r+b)/1
V=r+b

Water displacement with rock off boat:

M=DV

V=Water displaced
D=Water density (since we are measuring water displaced we use the density of the water not the rock)
r=Mass of Rock
b=Mass of Boat

V=r/D+b/D
V=r/1+b/1
V=r+b

right?

Not correct...

M=DV is true just by definition of density.

Water displacement happens because of boyancy. Boyancy if the effect that when an object is floating, the water that the object displaces has MASS equal to the MASS of the floating object. Water is displaced because a certain part of the floating object is submerged in the water. the VOLUME of the submerged part of the object is equal to the VOLUME of the water that is displaced.

A sunken object again displaces a volume of water that is equivalent to the object's volume. However, the mass of the object is more than the mass of that displaced water, that is why the object sinks: the boyant force is not enough to counteract the weight of the object.

When the rocks are in the boat, the shape of the boat allows it to displace a large enough volume of water that has a mass equal to the combined mass of the rocks and boat.

When the rocks are out of the boat, the boat displaces a volume of water that has mass equal to the boat's mass. The rocks however are displacing a volume of water equal to their volume, but that water has mass less than the mass of the rocks.

Therefore when the rocks were in the boat, the whole system displaced more water because it displaced a higher mass of water (and therefore a higher volume of water if we assume the density of water stays consistent)

If there were objects in the boat that had density equal to that of water, tossing them overboard would not raise or lower the level of water.

If you had balloons in the boat and tossed them overboard, well they would float and you wouldn't have any different of a situation than when they were in the boat and again the water level would stay the same.

there is no way to make the water level go up.

And yes, this can be performed in an experiment. take a glass of water and make a boat out of styrofoam (or any light material that won't let water seep through) and put some pennies in the boat. Mark the level of the water on the side of the glass. then take the pennies out of the clay boat and drop them overboard into the water. Compare the water level to the mark you made. If you had enough pennies in there to make a measurable difference, you will see that the level of the water dropped.

[Fagulous]

I seriosly doubt anyone will get this, but try without going to google.



A bear walks south for one kilometer, then it walks west for one kilometer, then it walks north for one kilometer and ends up at the same point from which it started. What color was the bear?

Potter you're not that fucking smart, and give us all a little credit you fucking faggot.

I figured that out in 3rd grade, I'm sure a lot of other people here did too.

wtf? did ieevr say i was remotely smart? not at all. And i found that question on google, never heard of it before, and it sounded extremely hard to me. SORRYRYSYDHHJK

It's all good, it's just those were they type of questions the teachers would give my class in grade school. I assumed you were talking down to us.

How far can a dog run into the woods?

[hascoolnickname]

How far can a dog run into the woods?

the middle?
amismart?